Question 413882
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Hi
Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
 y = x^2+2x+1           |Completing the square
 y = (x+1)^2       |Vertex is Pt(-1,0)& a Minimum as Parbola opens upward (a> 0)    x = -1, the line of symmetry
 0 = (x+1)^2       x = -1  
{{{drawing(300,300,   -10,10,-10,10, blue(line(-1,10,-1,-10)),   grid(1),
circle(-1, 0,0.4),
circle(-1,0,0.4),
graph( 300, 300, -10,10,-10,10,0, x^2+2x+1      ))}}}