Question 413885
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Hi
Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
 y = -x^2+2x+3            |Completing the square
 y = -(x-1)^2 +4       |Vertex is Pt(1,4)& a Maximum as Parbola opens downward(a> 0)    x = 1, the line of symmetry
 0 = -(x-1)^2 + 4      4 = (x-1)^2        x = 1 ± 2  {-1,3}
{{{drawing(300,300,   -10,10,-10,10, blue(line(1,10,1,-10)),   grid(1),
circle(1, 4,0.4),
circle(-1,0,0.4),
circle(3,0,0.4),
graph( 300, 300, -10,10,-10,10,0, -x^2+2x+3     ))}}}