Question 413888
  <pre><font face = "Times" size = 3 color = "indigo"><b>
Hi
Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
 y = x^2-2x-3            |Completing the square
 y = (x-1)^2 -4        |Vertex is Pt(1,-4)& a Minimum as Parbola opens upward (a> 0) x=1, the line of symmetry
 0 = (x-1)^2 -4      4 = (x-1)^2        x = 1 ± 2  {-1,3}
{{{drawing(300,300,   -10,10,-10,10, blue(line(1,10,1,-10)),   grid(1),
circle(1, -4,0.4),
circle(-1,0,0.4),
circle(3,0,0.4),
graph( 300, 300, -10,10,-10,10,0, x^2-2x-3    ))}}}