Question 413904
You can solve this with elimination quite easily.
{{{2x-7y=8}}}
{{{x-4y=3}}}
Multiply your second equation by negative 2, and add the systems.
{{{2x-7y=8}}} + {{{(-2)}}}*{{{x-4y=3}}} =
{{{2x-7y=8}}} + {{{-2x+8y=-6}}} = 
{{{2x-2x-7y+8y=8-6}}} = {{{y=2}}}
Plug y=2 back into either equation to solve for x.
{{{2x-7(2)=8}}}
{{{2x=22}}}
{{{highlight(x=11)}}}
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There are many other methods for solving this, but hopefully this helps.  I have also provided another method below.
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*[invoke linear "x", "y", 2, -7, 8, 1, -4, 3 ]