Question 413646
5x^2=11x+17
First you transfer the terms to left side of the = sign.
5x^2-11x-17=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(11+-sqrt[-11^2-4*5*17])/2*5
x=(11+-sqrt[121-340])/10
x=(11+-sqrt-219)/10
x=(11+-14.8i)/10
x=11/10+-1.48i
x=1.1+-1.48i ans.