Question 413611
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Let *[tex \Large x] represent the number.  Then *[tex \Large \frac{1}{x}] is the reciprocal of the number and *[tex \Large \frac{2}{x^2}] is two times the reciprocal squared.  The sum is 3 so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \frac{1}{x}\ +\  \frac{2}{x^2}\ =\ 3]


Multiply by *[tex \Large x^2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ x\ +\ 2\ =\ 3x^2]


Standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ 3x^2\ -\ x\ -\ 2\ =\ 0]


Factor and solve the quadratic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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