<PRE><B>Question 413622</B>
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Let *[tex \Large x] represent the smaller of the two angles.  Then *[tex \Large 9x] must represent the larger one.  The sum of the measures of two complementary angles is *[tex \Large 90^\circ], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 9x\ =\ 90]


Just solve for *[tex \Large x] to get one of the angles.  Multiply by 9 (or subtract from 90) to get the other.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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