Question 409204
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Hi
circle whose diameter has endpoints of (3, 0) and (7, 10)
(3, 0) and 
(7, 10) Midpoint is   (5,5)             |  ( {{{(x[1] + x[2])/2}}}, {{{(y[1] + y[2])/2  )}}})
(3, 0) and 
(7, 10  D = sqrt( (-4)^2 + (-10)^2))        |  D = {{{sqrt ((x1-x2)^2+(y1-y2)^2))}}} 
  D = sqrt(116) = 2sqrt(29) and r = sqrt(29)
 Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}

where Pt(h,k) is the center and r is the radius
   (x-5)^2 + (y-5)^2 = 29
{{{drawing(300,300,   -10,10,-10,10,  grid(1),
circle(5, 5,0.4),
line(3,0,7,10),
circle(5, 5,5.385),
graph( 300, 300, -10,10,-10,10))}}}