Question 413566
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Hi
Find the equation of the perpendicular bisector of the interval joining 
(-5,2) and (3,-4). 
Determining the slope of the line containing this segment: 
(-5,2) and 
(3,-4)  m = 6/-8 = -3/4                   | {{{m =(y[2] - y[1])/(x[2] - x[1])}}}
Finding the Midpoint of the segment
(-5,2) and 
(3,-4   Midpoint is Pt(-1,-1)             | ({{{(x[1] + x[2])/2}}}, {{{(y[1] + y[2])/2}}})
Line perpendicular(slope m = 4/3) passing thru Pt(-1,-1)
  y = (4/3)x + b  |using ordered pair pt(-1,-1) to solve for b
 -1 = -4/3 + b
 1/3 = b
   y = (4/3)x + 1/3  OR 4x - 3y = -1 in standard form.
{{{drawing(300,300,   -6, 6, -6, 6,  grid(1),
circle(-5, 2,0.3),
circle(3, -4,0.3),
line(-5,2,3,-4),
circle(-1,-1,0.3),
graph( 300, 300, -6, 6, -6, 6,0,(4/3)x + 1/3 ))}}}