Question 413525


{{{x+y=10}}}..........1
{{{y=x+8}}}...........2....substitute {{{y}}} in 1


{{{x+y=10}}}..........1


{{{x+x+8=10}}}.


{{{2x=10-8}}}.

{{{2x=2}}}.

{{{x=2/2}}}...

{{{x=1}}}....now sub. in 2 and find {{{y}}}


{{{y=x+8}}}...........2.


{{{y=1+8}}}


{{{y=9}}}..

so, your solutions are: {{{x=1}}} and {{{y=9}}}