Question 413148
{{{highlight(a=arctan(35/d))}}}

After drawing this out, you have a right triangle with a base of d, a height of 35, it has a right angle, and angle "a" at the bottom.  If you were to try and solve for a, you can use "sohcahtoa", which then gives you the expression:
{{{tan(a)=(35/d)}}}={{{highlight(a=arctan(35/d))}}}