Question 44061
    solve the following problem, be sure to show the equation used for the solution.
    The lenght....L SAY
 of a rectangle is 2in. more than twice its width....W SAY
TWICE WIDTH =2W
2" MORE=2W+2
L=2W+2
PERIMETER=2(L+W)=2(2W+2+W)=34
3W+2=34/2=17
3W=17-2=15
W=15/3=5
L=2W+2=2*5+2=12
 if the perimeter of the retangle is 34 in., find the dimensions of the rectangle.