Question 412889
9-4x^2 over 6x^2-5x-6

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9-4x^2 = (3+2x)(3-2x)  difference of two squares
6x^2-5x-6=(3x+2)(2x-3) factored form
=-(3x+2)(3-2x)
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(9-4x^2)/(6x^2-5x-6)
=(3+2x)(3-2x)/-(3x+2)(3-2x)
=-(3+2x)/(3x+2)