Question 412812
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The area of a rectangle is given by multiplying the length times the width.  Therefore, if you know the length and the area, you can find the width by dividing the area by the length.


The perimeter is given by multiplying the length by 2 and adding that to the width multiplied by 2.


So, all you have to do is, starting with the second line in your table, divide the number in the second column by the number in the first column.  Multiply the result of your division by 2 and add that to the number in the first column multiplied by 2.  Except for the first and last entries in the table, you should get the same answer every time, and that is your fixed perimeter.


The table gives you a set of points *[tex \Large (x,y)] where the number in the first column is the *[tex \Large x] value and the number in the second column is the *[tex \Large y] value.  Plot your set of points and draw a smooth curve.  It should look like this when you are done:


{{{drawing(
500, 500, -10,10,-2,18,
grid(1),
graph(
500, 500, -10,10,-2,18,
8x-x^2))}}}


But you should only graph the part that is in the first quadrant.  The highest point in the graph, namely the point *[tex \Large (4,16)] is the vertex.  In this particular case, because you have a parabola (notice the spelling -- mine is correct) that opens downward, the vertex is a local maximum of the function.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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