Question 412586
<font face="Times New Roman" size="+2">


Use the quadratic formula to calculate the two complex roots of the equation.  Then multiply the two roots.  They are complex conjugates, so the result is the SUM of two squares (not the difference because *[tex \Large i^2\ =\ -1]).


The sum of the two roots is simply two times the real part because the imaginary parts are of opposite signs.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>