Question 412542
Find the slope of a line perpendicular to the line that passes through the following points: (3, 9) and (7, 15)


Perpendicular lines have slopes which are negative reciprocals


y2 - y1
-------- = slope
x2 - x1


15 - 9
------- {substituted coordinates into slope formula}
7 - 3


6
-- {subtracted}
4


= 3/2 {reduced}


the perpendicular slope would be -2/3 {the negative reciprocal of 3/2}
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