Question 43854
The vertex is located between this, so: V(4,1)
Remember: {{{p = 1/(4a)}}}
{{{-1 = 1/(4a)}}}
{{{-4a = 1}}}
{{{-a = 1/4}}}
Use Form:
{{{y = a(x - h)^2 + k}}}
{{{y = (-1/4)(x - 4)^2 + 1}}}
{{{y = (-1/4)(x^2 - 8x + 16) + 1}}}
{{{y = (-1/4)x^2 + 2x - 4 + 1}}}
{{{y = (-1/4)x^2 + 2x - 3}}}
{{{ graph( 600, 600, -10, 10, -10, 10, (-1/4)x^2 + 2x - 3, 2 ) }}}