Question 412481
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ h)^2\ +\ (y\ -\ k)^2\ =\ r^2]


is the equation of a circle centered at *[tex \Large (h,k)] and radius *[tex \Large r]


Hint:  Rewrite your equation as:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(x\ -\ (-1)\right)^2\ +\ (y\ -\ 1)^2\ =\ 4^2]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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