Question 412458
  <pre><font size = 3 color = "indigo"><b>
Hi
given a normal distribution with a mean of 6000 and standard diviation 1500
 what score is at the 30th percentile?
*Note: {{{z = blue(x - mu)/blue(sigma)}}}
      -.5244 = (x -6000)/1500   |NORMSINV(0.3) = -.5244
     -.5244*1500 + 6000 = x = 5213.4
 
{{{drawing(300,300,-5,5,-1,1,blue(line(-.5244,5,-.5244,-5)), grid(1),graph( 300, 300,-5,5,-1,1,(1/sqrt(2*pi))*3^((-x^2/2)))) }}}