Question 412302
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Hi,
If I am understanding Your question properly:
{{{sqrt(7x+36) = x+4}}}   |squaring both sides of the Eq
 7x + 36 = (x+4)^2
 7x + 36 = x^2 + 8x + 16
   x^2 + x - 20 = 0
 (x+5)(x-4)=0 Note:SUM of the inner product(5x) and the outer product(-4x) = x
 (x+5)=0  x = -5  |Extraneous solution sqrt(1) &#8800; -1
 (x-4)=0  x = 4