Question 412305
5square root 4x-7=5square root8x+41
{{{5sqrt(4x-7)=5sqrt(8x+41)}}}

divide both sides by 5
{{{sqrt(4x-7)=sqrt(8x+41)}}}

take the square on both sides
{{{(4x-7)=(8x+41)}}}

add-8x to both sides
4x-8x-7=8x-8x+41
-4x=41+7
-4x=48
/-4
x=-12