Question 412151
<pre><font face = "consolas" color = "indigo" size = 4><b>
Start with by breaking {{{8yd^3}}} down to {{{8yd*yd*yd}}},
then writing those over 1:

{{{expr(8yd/1)expr(yd/1)expr(yd/1)}}}

Then multiply by three unit fractions to change each of the the yd. to ft.

{{{expr(8yd/1)expr(yd/1)expr(yd/1)expr(3ft/(1yd))expr(3ft/(1yd))expr(3ft/(1yd))}}}

Then multiply by three unit fractions to change each of the the ft. to in.

{{{expr(8yd/1)expr(yd/1)expr(yd/1)expr(3ft/(1yd))expr(3ft/(1yd))expr(3ft/(1yd))expr(12in/(1ft))expr(12in/(1ft))expr(12in/(1ft))expr(2.54cm/(1in))expr(2.54cm/(1in))expr(2.54cm/(1in))}}}

Then multiply by three unit fractions to change each of the the in. to cm.

{{{expr(8yd/1)expr(yd/1)expr(yd/1)expr(3ft/(1yd))expr(3ft/(1yd))expr(3ft/(1yd))expr(12in/(1ft))expr(12in/(1ft))expr(12in/(1ft))expr(2.54cm/(1in))expr(2.54cm/(1in))expr(2.54cm/(1in))}}}

Now we cancel the yd:

{{{expr(8cross(yd)/1)expr(cross(yd)/1)expr(cross(yd)/1)expr(3ft/(1cross(yd)))expr(3ft/(1cross(yd)))expr(3ft/(1cross(yd)))expr(12in/(1ft))expr(12in/(1ft))expr(12in/(1ft))expr(2.54cm/(1in))expr(2.54cm/(1in))expr(2.54cm/(1in))}}}

Now we cancel the ft:

{{{expr(8cross(yd)/1)expr(cross(yd)/1)expr(cross(yd)/1)expr(3cross(ft)/(1cross(yd)))expr(3cross(ft)/(1cross(yd)))expr(3cross(ft)/(1cross(yd)))expr(12in/(1cross(ft)))expr(12in/(1cross(ft)))expr(12in/(1cross(ft)))expr(2.54cm/(1in))expr(2.54cm/(1in))expr(2.54cm/(1in))}}}

Now we cancel the in:

{{{expr(8cross(yd)/1)expr(cross(yd)/1)expr(cross(yd)/1)expr(3cross(ft)/(1cross(yd)))expr(3cross(ft)/(1cross(yd)))expr(3cross(ft)/(1cross(yd)))expr(12cross(in)/(1cross(ft)))expr(12cross(in)/(1cross(ft)))expr(12cross(in)/(1cross(ft)))expr(2.54cm/(1cross(in)))expr(2.54cm/(1cross(in)))expr(2.54cm/(1cross(in)))}}}

And we have left:

{{{(8*3*3*3*12*12*12*2.54*2.54*2.54cm*cm*cm)/(1*1*1*1*1*1*1*1*1*1*1*1)}}}

And that calculates out to be

{{{6116438.864cm^3}}}

If you like you can cancel the units as you go instead of waiting till
the end.

Edwin</pre>