Question 412059
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Hi
Note:  finding the value of a 3x3 matrix is done as follows:
{{{(matrix(3,3,a1,b1,c1,a2,b2,c2,a3,b3,c3))}}} = a1(b2c3-c2b3) - b1(a2c3-c2a3) + c1(a2b3-b2a3) 
4x-y+2z=5
2y+z=4
4x+y+3z=10 
 

D = {{{matrix(3,3,4,-1,2,0,2,1,4,1,3)}}} = 0
    4*5 -(-1)1*-4 +2*-8 = 0
  this system has NO solution as D = 0