Question 412077
Hello, can somebody please help me with this question I don't understand it

The 8th term of an arithmetic sequence is 25 and the 20th term is -11. Find the first term of the sequence and the common difference and use those to write the general term.

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The other tutor's answer is wrong.


__, __, __, __, __, __, __, 25, __, __, __, __, __, __, __, __, __, __, __, -11, __, ...   

The general term of any arithmetic sequence is the formula
for the nth term which is

a<sub>n</sub> = a<sub>1</sub> + (n - 1)d

Substitute 8 for n:

a<sub>8</sub> = a<sub>1</sub> + (8 - 1)d

a<sub>8</sub> = a<sub>1</sub> + 7d

Substitute 25 for a<sub>8</sub>

25 = a<sub>1</sub> + 7d

a<sub>1</sub> + 7d = 25

----------------

a<sub>n</sub> = a<sub>1</sub> + (n - 1)d

Substitute 20 for n:

a<sub>20</sub> = a<sub>1</sub> + (20 - 1)d

a<sub>20</sub> = a<sub>1</sub> + 19d

Substitute -11 for a<sub>20</sub>

-11 = a<sub>1</sub> + 19d

a<sub>1</sub> + 19d = -11

Now we have the system of equations:

a<sub>1</sub> +  7d =  25
a<sub>1</sub> + 19d = -11

Solve the first one for a<sub>1</sub>
      a<sub>1</sub> =  25 - 7d

Substitute (25 - 7d) for a<sub>1</sub>

(25 - 7d) + 19d = -11
  25 - 7d + 19d = -11
       25 + 12d = -11
            12d = -36
              d = -3

             a<sub>1</sub> =  25 - 7d
             a<sub>1</sub> =  25 - 7(-3)
             a<sub>1</sub> =  25 + 21
             a<sub>1</sub> =  46

So a<sub>1</sub> = 46 is the first term of the sequence and d = -3 is the common
difference.   

So the arithmetic sequence is:

46, 43, 40, 37, 34, 31, 28, 25, 22, 19, 16, 13, 10, 7, 4, 1, -2, -5, -8, -11, -14, ...

The general term is found by substituting a<sub>1</sub> = 46 and d = -3 in the
formula for the nth term:

a<sub>n</sub> = a<sub>1</sub> + (n - 1)d

a<sub>n</sub> = 46 + (n - 1)(-3)

a<sub>n</sub> = 46 - 3(n - 1)

a<sub>n</sub> = 46 - 3n + 3

a<sub>n</sub> = 49 - 3n

That's the general term.

Edwin</pre>