Question 412049
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Hi
Geometric Series: {3,1.5, 0.75 ...} r = .5  
{{{sum( a[i], i=1, 6 )}}} = a(1-r^6)/(1-r)
{{{sum( a[i], i=1, 6 )}}} = 3(1-.5^6)/.5 = 3*.984375/.5 = 5.90625

Note:
|r|<1 {{{sum( a[i], i=1, infinity )}}} = a/(1-.5)=3/.5 = 6