Question 412009
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Hi
Hm...the system of linear equations You have picked has only 'one' solution:
solving by substitution method
y=1500+20x and 
y=3000+10x
1500+2x = 3000+10x
1200 = 8x
 150 = x and y = 1500 + 3000 = 4500

solving by elimination method
y=1500+20x and 
y=3000+10x

 y= 1500+20x and 
-y=-3000-10x    |multiplying 2nd equation thru by -1 and adding so as to eliminate y
 0 = -1500 +10x
1500 = 10x
 150 = x  and y = 1500 + 3000 = 4500

CHECKING our Answer(s)***
4500 = 3000 + 1500
4500 = 1500 + 3000