Question 411954
I need to give the exact and approximate solutions to 3 decimal places. 
(x-12)^2 - 12; 
My steps:
x-12= sqrt12; x-12 = - sqrt12 
exact solutions are 12+2 = sqrt 3 12-2 = sqrt 3.
x = 12 ± sqrt(12)
x = 12 ± 2sqrt(3)
I'm not sure if that's what you have.
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x =~ 15.464, 8.536  (not negative 8.536)
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Approximate solutions are 15.464, -8.536