Question 44010
2a^3-52a^2b+96ab^2
"a" is  present in each of the terms, so factorise:
a(2a^2-52ab+96b^2)
no inside the brackets you have a quadratic polynomial. Use {{{a = (-B +- sqrt( B^2-4*A*C ))/(2*A) }}}
where
A=2
B=-52b
C=96b^2
this gives:
{{{a = (52b +- sqrt( 2704b^2-768b^2 ))/4 }}}
{{{a = (52b +- sqrt( 1936b^2 ))/4 }}}
{{{a = (52b +- 44b)/4 }}}
{{{b=2}}} or {{{b=24}}}

I hope this helps.

P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would send me your feedback on my help to adam.chapman@student.manchester.ac.uk