Question 411711
(2,5)
3y-x=6   
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Solve for y
{{{3y=x+6}}}
{{{y=(1/3)x+2}}}
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{{{y=mx+b}}}  (m is the slope, b is the y-intercept.)
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For a line to be parallel to the above line, the slopes need to be the same.
{{{y=(1/3)x+b}}}
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Now plug in your x and y from the point you were given.  (2,5), x=2, y=5.
{{{5=(1/3)2+b}}}
Solve for b
{{{5-2/3=b}}}
{{{15/3-2/3=b}}}
{{{13/3=b}}}
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Therefore, the answer is:
{{{highlight(y=(1/3)x+13/3)}}}