Question 411667
{{{16x^2-40x=-25}}}
{{{16x^2-40x+25=0}}}
Using the Quadratic Equation=
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-(-40) +- sqrt( (-40)^2- (4)(16)(25) ))/(2*16)}}}
{{{x = (40 +- sqrt(1600- 1600))/(32)}}}
{{{x = (40 +- sqrt(0))/(32)}}}
{{{x = (40 +- 0)/(32)}}}
{{{x = (40-0)/32 }}} or {{{(40+0)/32}}}
{{{x = 40/32}}} or {{{40/32}}}
{{{x = (5)/(4)}}} or {{{(5)/(4)}}}