Question 411591
{{{sqrt(360)}}}
First thing you need to do is a prime factorization of the inside term.
{{{360 = 36*10 = 6*6*10 = 6*6*2*5}}}  I realize that 6 is not a prime number, however, since it comes up an even number of times in the factorization, there is no reason to factor it further.  Since 6 came up twice, you can move one outside of the square root sign and cross the other one out.  {{{6sqrt(2*5)}}}  Since there are no other numbers that come up more than once, you are done.  {{{highlight(6sqrt(10))}}}
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{{{sqrt(40)}}}
{{{40 = 10*4 = 2 * 5 * 2 * 2}}}
Therefore, you can move 1 of the 2's outside, and cross one of them out.
{{{highlight(2sqrt(10))}}}
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{{{sqrt(240)}}}
{{{240 = 6* 40 = 2 * 3 * 10 * 4 = 2 * 3 * 2 * 5 * 2 * 2}}}
Therefore you can take two 2's out and cross the other two out.
{{{highlight(4sqrt(15))}}}