Question 411469
 graph the quadratic function 
f(x)=4(x+5)^2-1
Since 4>0 the parabola opens up.
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Vertex = (-5,-1)
y-intercept = (0,99)
{{{graph(400,300,-10,10,-10,125,4(x+5)^2-1)}}}
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Cheers,
Stan H.
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