Question 411324
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Hi
{{{5*4^(3n+1)/(20*8^(2n))}}}
{{{5*(2^2)^(3n+1)/(20*(2^3)^(2n))}}}
{{{5*2^(2(3n+1))/(20*2^(3(2n)))}}}
{{{5*2^(6n+2)/(20*2^(6n))= 5*2^(6n+2-6n)/(20) =5*2^2/20= 5*4/20}}} = 20/20 = 1