Question 411292
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Hi
2x^2-3x=20
2x^2-3x-20=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (3 +- sqrt(169 ))/(4) }}}
  x = (3 ± 13)/4
  x = 4
  x = -10/4 = -5/2

CHECKING our Answer***
 (x-4)(x+5/2) = 0
 {{{x^2 -(3/2)x - 20/2 = 0}}}
 2x^2 -3x-20 = 0