<PRE><B>Question 411281</B>
 Do I leave my answer in fraction form or in whole number form? How do I know? 
x^2-3x-28=0
-3+-sqrt((3)^2-4(1)(-28))/(2(1))
-3+-sqrt(9+112)/(2)
-3+-sqrt(121)/(2) 
x=(4)/(1) and x=-(7)/(1)
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Should be:
x = [-b +- sqrt(b^2-4ac)]/(2a)
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x = [3 +- sqrt(9-4*1*-28)]/(2
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x = [3 +- sqrt(121)]/2
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x = [3+-11]/2
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x = -8/2 or x = 14/2
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x = -4 or x = 7
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Cheers,
Stan H.
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