Question 411244
Two jets leave an air base at the same time and travel in opposite directions. One jet travels 92 slower than the other. If the two jets are 10,602 apart after 9 hours, what is the rate of each jet? 
Sol'n:
note: your lacking of units...
St=S1+S2
10,602=9v+9(v-92)
10,602=18v-828
18v=10,602+828
18v=11,430
v=635
v-92=543


thus the rate are 635 & 543 ----answer

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