Question 411177
y = -0.005x^2 + x + 9 
A) What is the maximum height attained by the ball?
Max occurs when x = -b/2a = -1/(2*-0.005) = 100 seconds
Max height is f(100) = -0.005(100)^2+100+9 = 59
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B) How far has it traveled horizontally when it hits the ground? Round your answer to the nearest foot.
It started at f(0) = 9 ft and will be back on the ground at f(x) = 0 ft.
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Solve -0.005x^2+x+9 = 0
Solve for "x" using the Quadratic Formula.
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Cheers,
Stan H.
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