Question 410620
graph the equation x^2+8y=0

..

change to standard form, y=A(x-h)^2+k,with (h,k) being the (x,y) coordinates of the vertex. In the given problem, (h,k) =(0,0)
x^2+8y=0
8y=-x^2
y=-(1/8)x^2
This is a parabola that opens upwards, with vertices at (0,0)
..
{{{ graph( 300, 300, -10, 10, -10, 10, -(1/8)x^2) }}}