Question 411149
Solve the Logarithmic equation
ln(ln(x^2))=0
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A logarithim can be defined as follows:
The base raised to the logarithm of the number is=to the number.
In the first step,the base=e,the logarithm of the number is=0,and the number=ln(x^2).  This is also the exponential form of a logarithm.
ln(ln(x^2))=0. In the second step with the same base=e,the logarithm of the number is=1,and the number is x^2.
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first step:
e^0=ln(x^2)
1=ln(x^2)
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second step:
1=ln(x^2)
e^1=x^2
x=+-sqrt(e)
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Check:
ln(ln(x^2))=0
ln[x^2]=ln[(+-sqrt(e)^2]=lne=1
then,ln(ln(x^2))
=ln(1)=0
so,ln(ln(x^2))=0