Question 411172


{{{(2x+3)(x+4)=1}}}....multiply



{{{2x^2+8x+3x+12=1}}}


{{{2x^2+11x+12-1=0}}}


{{{2x^2+11x+11=0}}}......use quadratic formula to find roots


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ......{{{a=2}}}, {{{b=11}}}, and {{{c=11}}}


{{{x = (-11 +- sqrt( 11^2-4*2*11 ))/(2*2) }}} 



{{{x = (-11 +- sqrt( 121-88 ))/4 }}} 



{{{x = (-11 +- sqrt( 33 ))/4 }}} 


{{{x = (-11 +- (5.75))/4 }}} 


{{{x1 = (-11 + (5.75))/4 }}} 


{{{x1 = (-5.25)/4 }}} 


{{{x1 = -1.31 }}}


{{{x2 = (-11 - (5.75))/4 }}} 


{{{x2 = (-16.75)/4 }}} 


{{{x2 = -4.19 }}}