Question 411074
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Hi
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \LARGE\ \ log_33 + log_3x = log_3(3x) = 5 ]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  3^5 = 3x
   81 = x