Question 43984
{{{9x^3-24x^3+16x^2=0}}}
simplify
{{{-15x^3+16x^2=0}}}
we cannot easily solve a cubic polynomial but we can solve a quadratic

now use the quadratic solver {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
where
a=-15
b=16
c=0
this gives {{{x=(-16+-sqrt(16^2-0))/-30)}}}
{{{x=(-16+-16)/-30}}}

which gives solutions x=0 or x=16/15