Question 411074
{{{log(3,3)+log(3,x)=5}}}
Use formulas {{{log(c,a)+log(c,b)=log(c,(ab))}}}, so {{{log(3,3)+log(3,x)=log(3,3x)}}}
__________{{{a=(log(c,c^a))}}}, so {{{5=log(3,3^5)=log(3, 243)}}}
{{{log(3,3x)=log(3,243)}}}
{{{3x=243}}}
{{{x=243/3}}}
{{{x=81}}}
.
Check the answer
{{{log(3,3)+log(3,81)=5}}}
{{{1+4=5}}}
{{{5=5}}}- correct
Answer x=81