Question 410935
Not quite. Use {{{ln(a) - ln(b) = ln(a/b)}}}, so


{{{ln(5) - ln(x) = ln(5/x) = 3}}}


Raise each side to the base e, i.e.


{{{5/x = e^3}}}


{{{xe^3 = 5}}} (cross-multiplying)


{{{x = 5/(e^3)}}}