Question 410644
a rectangle has a perimeter of 80 feet, its length is 8 feet more than the width.
 What is the length and the width.
:
The perimeter:
2L + 2W = 80
simplify, divide by 2
L + W = 40
:
It says,"its length is 8 feet more than the width"; therefore:
L = W + 8
;
Replace L with (W+8) in the 1st simplified equation
(W+8) + W = 40
2W = 40 - 8
2W = 32
W = {{{32/2}}}
W = 16 ft is the width:
:
I'm going to let you find the length, then check the solutions in the perimeter equation.