Question 410709
f(x)= 6/x+3 
g(x)= 2/3x 
-----------------
(f o g)(x)
= f[(2/3)x] = 6/[(2/3)x+3]
------------------ 

(g o f)(x)
= g[6/(x+3)]
----
= (2/3)[6/(x+3)]
---
= 4/(x+3)
==============
Cheers,
Stan H.
==============