Question 410508
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Hi
line passing through (-2,5)and perpendicular to the graph of y=(-1/8)x + 19/4 
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
Line perpendicular will have slope m = 8 as  8/1*(-1/8) = -1
  y = 8x + b |using ordered pair Pt(-2,5) to solve for b
  5 = -16 + b
   21 = b  
 y = 8x + 21