Question 410608
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Hi
Line passing thru Pt(2,6) and parallel to x+6y=5
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
x+6y=5  OR y = (-1/6)x + 5/6  |slope of these parallel lines is m = -1/6
New Line
  y = (-1/6)x + b  |using ordered pair Pt(2,6) to solve for b
  6 = -1/3 + b
 18/3 + 1/3 = b
      19/3 = b
    y = (-1/6)x + 19/3     |y-intercept is Pt(0,19/3)