Question 410610
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Hi
Line passing thru Pt(-7,9) and parallel to 3x=8y+5
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
3x=8y+5  OR y = (3/8)x - 5/8  |slope of these parallel lines is m = 3/8
New Line
  y = (3/8)x + b  |using ordered pair Pt(-7,9) to solve for b
  9 = (3/8)*-7 + b
 72/8 + 21/8 = b
      93/8 = b
    y = (3/8)x  + 93/8      |y-intercept is Pt(0,93/8)