<PRE><B>Question 410614</B>
  &lt;pre&gt;&lt;font size = 3 color = &quot;indigo&quot;&gt;&lt;b&gt;
Hi
Line passing thru Pt(8,-5) and parallel to 7x + 3y = 5
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
 7x + 3y = 5  OR y = (-7/3)x + 5/3  |slope of these parallel lines is m =(-7/3)
New Line
  y = (-7/3)x + b  |using orderedpari Pt(8,-5) to solve for b
 -5 = (-7/3)*8 + b
 -40/8 + 56/8 = b
        2 = b
   y = (-7/3)x + 2  |y-intercept is Pt(0,2)
{{{drawing(300,300,   -6, 6, -6, 6, grid(1),
circle(8, -5,0.3),
circle(0, 5/3,0.3),
circle(0, 2,0.3),
graph( 300, 300, -6, 6, -6, 6,0,(-7/3)x + 5/3,(-7/3)x + 2 ))}}}
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